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Popular >

integral of 1/(u+1)

Solution

\int \frac{1}{u + 1} d u

Solution

ln ∣ u + 1 ∣ + C

Solution steps

\int \frac{1}{u + 1} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= ln ∣ v ∣

Substitute back

v = u + 1

= ln ∣ u + 1 ∣

Add a constant to the solution

= ln ∣ u + 1 ∣ + C

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Frequently Asked Questions (FAQ)

What is the integral of 1/(u+1) ?
The integral of 1/(u+1) is ln|u+1|+C