What is the tangent of f(x)=3x^2-x^3,(1,2) ?

The tangent of f(x)=3x^2-x^3,(1,2) is y=3x-1

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tangent of f(x)=3x^2-x^3,(1,2)

tangent of

f (x) = 3 x^{2} - x^{3}, (1, 2)

y = 3 x - 1

Solution steps

Find the slope of

f (x) = 3 x^{2} - x^{3} : \frac{df ( x )}{d x} = 6 x - 3 x^{2}

Compute the slope of

f (x) = 3 x^{2} - x^{3}

(1, 2) : m = 3

Find the line with slope m=

3

and passing through

(1, 2) : y = 3 x - 1

y = 3 x - 1

(- 3, - 5), (- 2, - 3)

\frac{d}{d x} ((1 + x) e^{- x})

\int 8 x^{2} d x

4 y^{^{''}} - 5 y^{^{'}} = 0, y (- 2) = 0, y^{^{'}} (- 2) = 7

s + 1

What is the tangent of f(x)=3x^2-x^3,(1,2) ?
The tangent of f(x)=3x^2-x^3,(1,2) is y=3x-1