What is the solution for y^'=4.9-22.22y ?

The solution for y^'=4.9-22.22y is y=-(e^{-22.22000…t-c_{1}})/(22.22)+(4.9)/(22.22)

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y^'=4.9-22.22y

y^{^{'}} = 4.9 - 22.22 y

y = - \frac{e ^{- 22.22000 \dots t - c_{1}}}{22.22} + \frac{4.9}{22.22}

Solution steps

y^{'} (t) = 4.9 - 22.22 y

Solve separable ODE:

y = - \frac{e ^{- 22.22000 \dots t - c_{1}}}{22.22} + \frac{4.9}{22.22}

y = - \frac{e ^{- 22.22000 \dots t - c_{1}}}{22.22} + \frac{4.9}{22.22}

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What is the solution for y^'=4.9-22.22y ?
The solution for y^'=4.9-22.22y is y=-(e^{-22.22000…t-c_{1}})/(22.22)+(4.9)/(22.22)