What is the solution for y^'+1/x y=x^2y^1 ?

The solution for y^'+1/x y=x^2y^1 is y=(e^{(x^3+c_{1})/3})/(x)

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y^'+1/x y=x^2y^1

y^{^{'}} + \frac{1}{x} y = x^{2} y^{1}

y = \frac{e ^{\frac{x ^{3} + c _{1}}{3}}}{x}

Solution steps

y^{'} (x) + \frac{1}{x} y = x^{2} y^{1}

Solve separable ODE:

y = \frac{e ^{\frac{x ^{3} + c _{1}}{3}}}{x}

y = \frac{e ^{\frac{x ^{3} + c _{1}}{3}}}{x}

\int \frac{1}{3 ^{x}} d x

y^{^{'}} = 2 y + 1

cos (t - \frac{2 π}{3})

x \to 0 lim (\frac{7 ^{x} - 4 ^{x}}{x})

\int \frac{x - 3}{8 x - x ^{2}} d x

What is the solution for y^'+1/x y=x^2y^1 ?
The solution for y^'+1/x y=x^2y^1 is y=(e^{(x^3+c_{1})/3})/(x)