What is (\partial)/(\partial x)(ln(x^2y^2)) ?

The answer to (\partial)/(\partial x)(ln(x^2y^2)) is 2/x

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(\partial)/(\partial x)(ln(x^2y^2))

\frac{\partial}{\partial x} (ln (x^{2} y^{2}))

\frac{2}{x}

Solution steps

\frac{\partial}{\partial x} (ln (x^{2} y^{2}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x ^{2} y ^{2}} \frac{\partial}{\partial x} (x^{2} y^{2})

= \frac{1}{x ^{2} y ^{2}} \frac{\partial}{\partial x} (x^{2} y^{2})

\frac{\partial}{\partial x} (x^{2} y^{2}) = 2 y^{2} x

= \frac{1}{x ^{2} y ^{2}} \cdot 2 y^{2} x

Simplify

\frac{1}{x ^{2} y ^{2}} \cdot 2 y^{2} x : \frac{2}{x}

= \frac{2}{x}

\frac{d}{d x} (e^{\frac{in x}{2 x}})

\int \frac{sin ( 2 θ )}{cos ( 2 θ )} d θ

\frac{d}{d x} (y \cdot sin (x))

x \to 2 - lim (x - 2)

- \frac{1}{x}

What is (\partial)/(\partial x)(ln(x^2y^2)) ?
The answer to (\partial)/(\partial x)(ln(x^2y^2)) is 2/x