What is (\partial)/(\partial y)(y^2+y) ?

The answer to (\partial)/(\partial y)(y^2+y) is 2y+1

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(\partial)/(\partial y)(y^2+y)

\frac{\partial}{\partial y} (y^{2} + y)

2 y + 1

Solution steps

\frac{\partial}{\partial y} (y^{2} + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (y) = 1

= 2 y + 1

\int 10 tan^{3} (x) sec (x) d x

\int \frac{x ^{2} + 1}{x} d x

\int_{1}^{\infty} \frac{1}{x + 1} d x

f (x) = \frac{x ^{4}}{8} + \frac{1}{4 x ^{2}}

y = lo g_{x} (e)

What is (\partial)/(\partial y)(y^2+y) ?
The answer to (\partial)/(\partial y)(y^2+y) is 2y+1