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Popular >

derivative of-ln(2x-3)

Solution

\frac{d}{d x} (- ln (2 x - 3))

Solution

- \frac{2}{2 x - 3}

Solution steps

\frac{d}{d x} (- ln (2 x - 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (2 x - 3))

Apply the chain rule:

\frac{1}{2 x - 3} \frac{d}{d x} (2 x - 3)

= \frac{1}{2 x - 3} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= - \frac{1}{2 x - 3} \cdot 2

Simplify

- \frac{1}{2 x - 3} \cdot 2 : - \frac{2}{2 x - 3}

= - \frac{2}{2 x - 3}

Popular Examples

tangent of y=2x^3-x^2+4,(2,16)tangent of

y = 2 x^{3} - x^{2} + 4, (2, 16)

area x=(y^2-1)/3 ,x=3+y area

x = \frac{y ^{2} - 1}{3}, x = 3 + y

derivative of-2ln(x+x^2-4+e^x+x^e)

\frac{d}{d x} (- 2 ln (x) + x^{2} - 4 + e^{x} + x^{e})

(\partial)/(\partial x)(2yz)

\frac{\partial}{\partial x} (2 yz)

limit as x approaches 6-of e^{3/(6-x)}

x \to 6 - lim (e^{\frac{3}{6 - x}})

Frequently Asked Questions (FAQ)

What is the derivative of-ln(2x-3) ?
The derivative of-ln(2x-3) is -2/(2x-3)
What is the first derivative of-ln(2x-3) ?
The first derivative of-ln(2x-3) is -2/(2x-3)