What is the integral of cot(3-7x) ?

The integral of cot(3-7x) is -1/7 ln|sin(3-7x)|+C

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integral of cot(3-7x)

\int cot (3 - 7 x) d x

- \frac{1}{7} ln ∣ sin (3 - 7 x) ∣ + C

Solution steps

\int cot (3 - 7 x) d x

Apply u-substitution

: \int - \frac{1}{7} cot (u) d u

= \int - \frac{1}{7} cot (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} \cdot \int cot (u) d u

Rewrite using trig identities

= - \frac{1}{7} \cdot \int \frac{cos ( u )}{sin ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= - \frac{1}{7} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= - \frac{1}{7} ln ∣ v ∣

Substitute back

= - \frac{1}{7} ln ∣ sin (3 - 7 x) ∣

Add a constant to the solution

= - \frac{1}{7} ln ∣ sin (3 - 7 x) ∣ + C

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What is the integral of cot(3-7x) ?
The integral of cot(3-7x) is -1/7 ln|sin(3-7x)|+C