What is the sum from n=1 to infinity of nsin(1/n) ?

The sum from n=1 to infinity of nsin(1/n) is diverges

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sum from n=1 to infinity of nsin(1/n)

n = 1 \sum \infty n sin (\frac{1}{n})

diverges

Solution steps

n = 1 \sum \infty n sin (\frac{1}{n})

Apply Series Divergence Test:

diverges

= diverges

\frac{\partial}{\partial x} (2 + 3 x + 4 y)

\int_{0}^{2} (4 - x^{2}) d x

\frac{2 s}{s ^{2} + 8 s + 25}

\frac{d x}{d t} - 5 x = 2 t

10 x

What is the sum from n=1 to infinity of nsin(1/n) ?
The sum from n=1 to infinity of nsin(1/n) is diverges