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Popular >

y^'+2xy=4x

Solution

y^{^{'}} + 2 x y = 4 x

Solution

y = e^{- x^{2} + c_{1}} + 2

Solution steps

y^{'} (x) + 2 x y = 4 x

Solve separable ODE:

y = e^{- x^{2} + c_{1}} + 2

y = e^{- x^{2} + c_{1}} + 2

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\frac{e ^{- 2 s}}{s ( s + 1 )}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=4x ?
The solution for y^'+2xy=4x is y=e^{-x^2+c_{1}}+2