What is the derivative of (4x/(x+1)) ?

The derivative of (4x/(x+1)) is 4/((x+1)^2)

What is the first derivative of (4x/(x+1)) ?

The first derivative of (4x/(x+1)) is 4/((x+1)^2)

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\frac{d}{d x} (\frac{4 x}{x + 1})

\frac{4}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 1) = 1

= 4 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{4}{( x + 1 ) ^{2}}

= \frac{4}{( x + 1 ) ^{2}}

\frac{\partial}{\partial y} (e^{\frac{y}{x}})

\int x (8 - 5 x^{2})^{3} d x

x^{3} - x

\frac{\partial}{\partial x} (\frac{3 x}{y ^{2}})

\int sin (4 x) cos (2 x) d x

What is the derivative of (4x/(x+1)) ?
The derivative of (4x/(x+1)) is 4/((x+1)^2)
What is the first derivative of (4x/(x+1)) ?
The first derivative of (4x/(x+1)) is 4/((x+1)^2)