What is the derivative of f(x)= 1/(\sqrt[3]{x)} ?

The derivative of f(x)= 1/(\sqrt[3]{x)} is -1/(3x^{4/3)}

What is the first derivative of f(x)= 1/(\sqrt[3]{x)} ?

The first derivative of f(x)= 1/(\sqrt[3]{x)} is -1/(3x^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- \frac{1}{3 x ^{\frac{4}{3}}}

Solution steps

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- \frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{3} x^{- \frac{1}{3} - 1}

Simplify

- \frac{1}{3} x^{- \frac{1}{3} - 1} : - \frac{1}{3 x ^{\frac{4}{3}}}

= - \frac{1}{3 x ^{\frac{4}{3}}}

e^{x^{3} + 10 x}

\int \frac{ln ( 9 x )}{x} d x

\frac{d ^{3}}{d x ^{3}} (x (2 x + 1)^{3})

- ln (x)

\frac{d}{d x} ((x - 2) x^{3})

What is the derivative of f(x)= 1/(\sqrt[3]{x)} ?
The derivative of f(x)= 1/(\sqrt[3]{x)} is -1/(3x^{4/3)}
What is the first derivative of f(x)= 1/(\sqrt[3]{x)} ?
The first derivative of f(x)= 1/(\sqrt[3]{x)} is -1/(3x^{4/3)}