What is the solution for y'=0.0012y(1000-y) ?

The solution for y'=0.0012y(1000-y) is y=(1.2)/(-e^{-1.2t-c_{1)}+0.0012}

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y'=0.0012y(1000-y)

y^{^{'}} = 0.0012 y (1000 - y)

y = \frac{1.2}{- e ^{- 1.2 t - c_{1}} + 0.0012}

Solution steps

y^{'} (t) = 0.0012 y (1000 - y)

Solve Bernoulli ODE:

y = \frac{1.2}{- e ^{- 1.2 t - c_{1}} + 0.0012}

y = \frac{1.2}{- e ^{- 1.2 t - c_{1}} + 0.0012}

\int 2 e^{2 θ} sin (2 θ) d θ

3 x^{\frac{3}{8}}

\frac{d}{d x} (x e^{x} + x)

\int (x - 2)^{- \frac{3}{2}} d x

f (x) = x^{9} ln (4 x)

What is the solution for y'=0.0012y(1000-y) ?
The solution for y'=0.0012y(1000-y) is y=(1.2)/(-e^{-1.2t-c_{1)}+0.0012}