What is the sum from n=0 to infinity of e^{-4n} ?

The sum from n=0 to infinity of e^{-4n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of e^{-4n}

n = 0 \sum \infty e^{- 4 n}

converges

Solution steps

n = 0 \sum \infty e^{- 4 n}

Apply Series Integral Test:

converges

= converges

y = \frac{x ^{6}}{2 - x ^{5}}

\frac{1}{e ^{x} - 1}

\frac{1}{2 x + 1}

\int \frac{2 x}{( 2 x ^{2} - 3 ) ^{3}} d x

\int arctan (4 t) d t

What is the sum from n=0 to infinity of e^{-4n} ?
The sum from n=0 to infinity of e^{-4n} is converges