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Popular >

integral from 1 to 2 of (x-1)

Solution

\int_{1}^{2} (x - 1) d x

Solution

\frac{1}{2}

+1

Decimal Notation

0.5

Solution steps

\int_{1}^{2} x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d x - \int_{1}^{2} 1 d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 1 d x = 1

= \frac{3}{2} - 1

Simplify

\frac{3}{2} - 1 : \frac{1}{2}

= \frac{1}{2}

Popular Examples

y^{^{'}} = 3 cos (t) - 2 y

tangent of 3/(x+2)tangent of

\frac{3}{x + 2}

integral from 1 to 3 of (4x^3-3x^2)

\int_{1}^{3} (4 x^{3} - 3 x^{2}) d x

inverse oflaplace 1/(s^2+s)inverse laplace

\frac{1}{s ^{2} + s}

(d^2y)/(dt^2)-e^2y=0

\frac{d ^{2} y}{d t ^{2}} - e^{2} y = 0

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x-1) ?
The integral from 1 to 2 of (x-1) is 1/2