What is the integral of sec(21w)tan(21w) ?

The integral of sec(21w)tan(21w) is 1/21 sec(21w)+C

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integral of sec(21w)tan(21w)

\int sec (21 w) tan (21 w) d w

\frac{1}{21} sec (21 w) + C

Solution steps

\int sec (21 w) tan (21 w) d w

Apply u-substitution

: \int \frac{1}{21} d u

= \int \frac{1}{21} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{21} u

Substitute back

u = sec (21 w)

= \frac{1}{21} sec (21 w)

Add a constant to the solution

= \frac{1}{21} sec (21 w) + C

n = 1 \sum \infty - \frac{1}{n ^{2}}

x^{10 x}

3 x + 10

\frac{\partial}{\partial z} (3 z)

\int 2 \cdot sin (x) d x

What is the integral of sec(21w)tan(21w) ?
The integral of sec(21w)tan(21w) is 1/21 sec(21w)+C