What is the integral from 0 to 4 of 1/(x^2) ?

The integral from 0 to 4 of 1/(x^2) is diverges

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integral from 0 to 4 of 1/(x^2)

\int_{0}^{4} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{4}

= [- \frac{1}{x}]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\frac{\partial}{\partial x} (ln (x^{2}))

\int - 2 cos (t) d t

\frac{d}{d x} ((3 x + 5)^{3} - 5 x)

\frac{\partial}{\partial x} (x e^{(\frac{y}{x})})

What is the integral from 0 to 4 of 1/(x^2) ?
The integral from 0 to 4 of 1/(x^2) is diverges