What is the derivative of y=(x+1/x)^5 ?

The derivative of y=(x+1/x)^5 is 5(x+1/x)^4(1-1/(x^2))

What is the first derivative of y=(x+1/x)^5 ?

The first derivative of y=(x+1/x)^5 is 5(x+1/x)^4(1-1/(x^2))

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derivative of

y = (x + \frac{1}{x})^{5}

5 (x + \frac{1}{x})^{4} (1 - \frac{1}{x ^{2}})

Solution steps

\frac{d}{d x} ((x + \frac{1}{x})^{5})

Apply the chain rule:

5 (x + \frac{1}{x})^{4} \frac{d}{d x} (x + \frac{1}{x})

= 5 (x + \frac{1}{x})^{4} \frac{d}{d x} (x + \frac{1}{x})

\frac{d}{d x} (x + \frac{1}{x}) = 1 - \frac{1}{x ^{2}}

= 5 (x + \frac{1}{x})^{4} (1 - \frac{1}{x ^{2}})

x \to 0 lim (x - 3)

\frac{\partial}{\partial y} (arctan (x + 4 y))

x \to 4 lim (3 x^{2})

f (x) = x + 6, at x = 10

10 \cdot \frac{1 - 3 s}{1 + 6 s}

What is the derivative of y=(x+1/x)^5 ?
The derivative of y=(x+1/x)^5 is 5(x+1/x)^4(1-1/(x^2))
What is the first derivative of y=(x+1/x)^5 ?
The first derivative of y=(x+1/x)^5 is 5(x+1/x)^4(1-1/(x^2))