What is the integral from 1 to 10 of (37)/(x^3) ?

The integral from 1 to 10 of (37)/(x^3) is 3663/200

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integral from 1 to 10 of (37)/(x^3)

\int_{1}^{10} \frac{37}{x ^{3}} d x

\frac{3663}{200}

Decimal Notation

18.315

Solution steps

\int_{1}^{10} \frac{37}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 37 \cdot \int_{1}^{10} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{10}

= 37 [- \frac{1}{2 x ^{2}}]_{1}^{10}

Compute the boundaries:

\frac{99}{200}

= 37 \cdot \frac{99}{200}

Simplify

= \frac{3663}{200}

\frac{d}{d x} (ln (\frac{2 x + 1}{2 x - 1}))

x \to a lim (1 - 1 - x^{2})

\frac{d y}{d x} = e^{(6 y + 3 x)}

\int (x^{4} - 2 x) d x

\frac{d}{d x} (x arcsec (x^{3}))

What is the integral from 1 to 10 of (37)/(x^3) ?
The integral from 1 to 10 of (37)/(x^3) is 3663/200