What is the derivative of (e^x/(x-1)) ?

The derivative of (e^x/(x-1)) is (e^xx-2e^x)/((x-1)^2)

What is the first derivative of (e^x/(x-1)) ?

The first derivative of (e^x/(x-1)) is (e^xx-2e^x)/((x-1)^2)

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\frac{d}{d x} (\frac{e ^{x}}{x - 1})

\frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) e ^{x}}{( x - 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x - 1) = 1

= \frac{e ^{x} ( x - 1 ) - 1 \cdot e ^{x}}{( x - 1 ) ^{2}}

Simplify

\frac{e ^{x} ( x - 1 ) - 1 \cdot e ^{x}}{( x - 1 ) ^{2}} : \frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

= \frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

\frac{d}{d x} (cos^{5} (3 x))

\int sin (\frac{x}{3}) cos (\frac{2 x}{3}) d x

\int x (e^{x}) d x

f (x) = \frac{2}{x - 1}, at x = - 2

\int \frac{x ( x - 1 )}{2} d x

What is the derivative of (e^x/(x-1)) ?
The derivative of (e^x/(x-1)) is (e^xx-2e^x)/((x-1)^2)
What is the first derivative of (e^x/(x-1)) ?
The first derivative of (e^x/(x-1)) is (e^xx-2e^x)/((x-1)^2)