What is the solution for (2xy^2+3x^2)dx+(2x^2y)dy=0 ?

The solution for (2xy^2+3x^2)dx+(2x^2y)dy=0 is y=(sqrt(-x^3+c_{1)})/x ,y=-(sqrt(-x^3+c_{1)})/x

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(2xy^2+3x^2)dx+(2x^2y)dy=0

(2 x y^{2} + 3 x^{2}) d x + (2 x^{2} y) d y = 0

y = \frac{- x ^{3} + c _{1}}{x}, y = - \frac{- x ^{3} + c _{1}}{x}

Solution steps

(2 x y^{2} + 3 x^{2}) d x + (2 x^{2} y) d y = 0

Solve exact ODE:

y = \frac{- x ^{3} + c _{1}}{x}, y = - \frac{- x ^{3} + c _{1}}{x}

y = \frac{- x ^{3} + c _{1}}{x}, y = - \frac{- x ^{3} + c _{1}}{x}

(2 x - 5) (x + 4)

\int 9 - t^{2} d t

\int cos (3 x) - sin (x) d x

x = y^{2} - 36, x = 36 - y^{2}

\frac{d}{d x} (6 ln (4 x))

What is the solution for (2xy^2+3x^2)dx+(2x^2y)dy=0 ?
The solution for (2xy^2+3x^2)dx+(2x^2y)dy=0 is y=(sqrt(-x^3+c_{1)})/x ,y=-(sqrt(-x^3+c_{1)})/x