What is the integral of 8/(sqrt(x)) ?

The integral of 8/(sqrt(x)) is 16sqrt(x)+C

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integral of 8/(sqrt(x))

\int \frac{8}{x} d x

16 x + C

Solution steps

\int \frac{8}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 8 \cdot 2 x^{\frac{1}{2}}

Simplify

8 \cdot 2 x^{\frac{1}{2}} : 16 x

= 16 x

Add a constant to the solution

= 16 x + C

\frac{d y}{d x} = 85 y x^{16}

\frac{d y}{d t} = - 5 y

n = 0 \sum \infty 2 \cdot (\frac{2}{5})^{n}

tan (x^{5})

\int (\frac{5}{t ^{2}} - 8 t^{6}) d t

What is the integral of 8/(sqrt(x)) ?
The integral of 8/(sqrt(x)) is 16sqrt(x)+C