What is the derivative of f(x)=2x^2-x+1 ?

The derivative of f(x)=2x^2-x+1 is 4x-1

What is the first derivative of f(x)=2x^2-x+1 ?

The first derivative of f(x)=2x^2-x+1 is 4x-1

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derivative of

f (x) = 2 x^{2} - x + 1

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 4 x - 1 + 0

Simplify

= 4 x - 1

\int - 8 x^{2} d x

\frac{e ^{- π (s)}}{s ^{3} + s}

\frac{d}{d x} ((x + \frac{1}{x})^{5})

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\int_{0}^{\infty} u e^{- u^{2}} d u

What is the derivative of f(x)=2x^2-x+1 ?
The derivative of f(x)=2x^2-x+1 is 4x-1
What is the first derivative of f(x)=2x^2-x+1 ?
The first derivative of f(x)=2x^2-x+1 is 4x-1