What is (\partial)/(\partial y)(e^{7yz}) ?

The answer to (\partial)/(\partial y)(e^{7yz}) is e^{7yz}*7z

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(\partial)/(\partial y)(e^{7yz})

\frac{\partial}{\partial y} (e^{7 yz})

e^{7 yz} \cdot 7 z

Solution steps

\frac{\partial}{\partial y} (e^{7 yz})

Treat

z

as a constant

Apply the chain rule:

e^{7 yz} \frac{\partial}{\partial y} (7 yz)

= e^{7 yz} \frac{\partial}{\partial y} (7 yz)

\frac{\partial}{\partial y} (7 yz) = 7 z

= e^{7 yz} \cdot 7 z

x \to 4 + lim (\frac{7 x - 1}{x - 4})

y^{^{''}} - 8 y^{^{'}} = 64 t

\frac{d}{d x} (3 + 7 x)

\int_{0}^{0} x^{2} d x

\frac{\partial}{\partial x} (ln (\frac{x}{20}))

What is (\partial)/(\partial y)(e^{7yz}) ?
The answer to (\partial)/(\partial y)(e^{7yz}) is e^{7yz}*7z