What is the derivative of f(x)=ln(x^3-1) ?

The derivative of f(x)=ln(x^3-1) is (3x^2)/(x^3-1)

What is the first derivative of f(x)=ln(x^3-1) ?

The first derivative of f(x)=ln(x^3-1) is (3x^2)/(x^3-1)

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derivative of

f (x) = ln (x^{3} - 1)

\frac{3 x ^{2}}{x ^{3} - 1}

Solution steps

\frac{d}{d x} (ln (x^{3} - 1))

Apply the chain rule:

\frac{1}{x ^{3} - 1} \frac{d}{d x} (x^{3} - 1)

= \frac{1}{x ^{3} - 1} \frac{d}{d x} (x^{3} - 1)

\frac{d}{d x} (x^{3} - 1) = 3 x^{2}

= \frac{1}{x ^{3} - 1} \cdot 3 x^{2}

Simplify

\frac{1}{x ^{3} - 1} \cdot 3 x^{2} : \frac{3 x ^{2}}{x ^{3} - 1}

= \frac{3 x ^{2}}{x ^{3} - 1}

x 64 - x^{2}, 0

\int - cos (\frac{x}{2}) d x

\frac{d}{d x} (x + \frac{7}{x})

\frac{d}{d x} ((x - 2 π)^{2})

\int \frac{1}{( x - 1 ) x ^{2} - 2 x - 3} d x

What is the derivative of f(x)=ln(x^3-1) ?
The derivative of f(x)=ln(x^3-1) is (3x^2)/(x^3-1)
What is the first derivative of f(x)=ln(x^3-1) ?
The first derivative of f(x)=ln(x^3-1) is (3x^2)/(x^3-1)