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Popular >

y^'=(4x)/(e^x)

Solution

y^{^{'}} = \frac{4 x}{e ^{x}}

Solution

y = 4 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}}) + c_{1}

Solution steps

y^{'} (x) = \frac{4 x}{e ^{x}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{4 x}{e ^{x}} d x

\int \frac{4 x}{e ^{x}} d x = 4 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}}) + c_{1}

y = 4 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}}) + c_{1}

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f(x)=sqrt(2-x^2)

f (x) = 2 - x^{2}

integral of (sin(x))/(e^{2x)}

\int \frac{sin ( x )}{e ^{2 x}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(4x)/(e^x) ?
The solution for y^'=(4x)/(e^x) is y=4(-x/(e^x)-1/(e^x))+c_{1}