What is (\partial)/(\partial x)(((x-y))/(c(a-b))) ?

The answer to (\partial)/(\partial x)(((x-y))/(c(a-b))) is 1/(c(a-b))

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(\partial)/(\partial x)(((x-y))/(c(a-b)))

\frac{\partial}{\partial x} (\frac{( x - y )}{c ( a - b )})

\frac{1}{c ( a - b )}

Solution steps

\frac{\partial}{\partial x} (\frac{( x - y )}{c ( a - b )})

Treat

c, a, b, y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{c ( a - b )} \frac{\partial}{\partial x} (x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{c ( a - b )} (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{c ( a - b )} (1 - 0)

Simplify

= \frac{1}{c ( a - b )}

\frac{d}{d t} (8 t)

\int \frac{5}{3} d x

\int_{6}^{8} \frac{x}{x ^{2} + 6 x + 13} d x

\frac{\partial}{\partial x} (ln (8 x))

\frac{d}{d x} (\frac{( e ^{x} - 1 )}{( e ^{x} + 1 )})

What is (\partial)/(\partial x)(((x-y))/(c(a-b))) ?
The answer to (\partial)/(\partial x)(((x-y))/(c(a-b))) is 1/(c(a-b))