What is area 5cos(3x),5sin(6x),[0, pi/6 ] ?

The answer to area 5cos(3x),5sin(6x),[0, pi/6 ] is 5/6

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area 5cos(3x),5sin(6x),[0, pi/6 ]

area

5 cos (3 x), 5 sin (6 x), [0, \frac{π}{6}]

\frac{5}{6}

Decimal Notation

0.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{6}} ∣ 5 cos (3 x) - 5 sin (6 x) ∣ d x

Solve

\int_{0}^{\frac{π}{6}} ∣ 5 cos (3 x) - 5 sin (6 x) ∣ d x : \frac{5}{6}

The area is:

= \frac{5}{6}

cos (t + π)

2 x^{3} + 3 x^{2} - 12 x + 9

x \to 0 + lim ((1 - x)^{\frac{1}{x}})

\frac{d y}{d x} = 3 x^{2} + 1

x \to 0 - lim (\frac{1}{x})

What is area 5cos(3x),5sin(6x),[0, pi/6 ] ?
The answer to area 5cos(3x),5sin(6x),[0, pi/6 ] is 5/6