What is the derivative of 4x^3-100x^2+600x ?

The derivative of 4x^3-100x^2+600x is 12x^2-200x+600

What is the first derivative of 4x^3-100x^2+600x ?

The first derivative of 4x^3-100x^2+600x is 12x^2-200x+600

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\frac{d}{d x} (4 x^{3} - 100 x^{2} + 600 x)

12 x^{2} - 200 x + 600

Solution steps

\frac{d}{d x} (4 x^{3} - 100 x^{2} + 600 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (100 x^{2}) + \frac{d}{d x} (600 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (100 x^{2}) = 200 x

\frac{d}{d x} (600 x) = 600

= 12 x^{2} - 200 x + 600

\frac{\partial}{\partial x} (sin (5 x))

\int (6 x - 1) cos (x) d x

\frac{d}{d x} (x^{l n (2)})

f (x) = 5 x + 11, at x = 5

\frac{d}{d x} (- 7 x^{2})

What is the derivative of 4x^3-100x^2+600x ?
The derivative of 4x^3-100x^2+600x is 12x^2-200x+600
What is the first derivative of 4x^3-100x^2+600x ?
The first derivative of 4x^3-100x^2+600x is 12x^2-200x+600