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Popular >

2y^{''}-8y=0

Solution

2 y^{^{''}} - 8 y = 0

Solution

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

Solution steps

2 y^{''} (t) - 8 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

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Frequently Asked Questions (FAQ)

What is the solution for 2y^{''}-8y=0 ?
The solution for 2y^{''}-8y=0 is y=c_{1}e^{2t}+c_{2}e^{-2t}