What is area y=3\sqrt[3]{x},0<= x<= 27 ?

The answer to area y=3\sqrt[3]{x},0<= x<= 27 is 729/4

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area y=3\sqrt[3]{x},0<= x<= 27

area

\frac{729}{4}

Decimal Notation

182.25

Solution steps

Apply the area formula:

Solve

The area is:

= \frac{729}{4}

\frac{\partial}{\partial x} (1 + x^{2} + y^{2})

\int_{1 - 2 x}^{1 + 2 x} t sin (t) d t

\frac{d}{d x} (\frac{x}{x ^{2} + 16})

\frac{d}{d x} (7 sin (3 x))

\int (x^{2} - 9 x + 4) d x

What is area y=3\sqrt[3]{x},0<= x<= 27 ?
The answer to area y=3\sqrt[3]{x},0<= x<= 27 is 729/4