What is the derivative of sec(8x^3+1) ?

The derivative of sec(8x^3+1) is sec(8x^3+1)tan(8x^3+1)*24x^2

What is the first derivative of sec(8x^3+1) ?

The first derivative of sec(8x^3+1) is sec(8x^3+1)tan(8x^3+1)*24x^2

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\frac{d}{d x} (sec (8 x^{3} + 1))

sec (8 x^{3} + 1) tan (8 x^{3} + 1) \cdot 24 x^{2}

Solution steps

\frac{d}{d x} (sec (8 x^{3} + 1))

Apply the chain rule:

sec (8 x^{3} + 1) tan (8 x^{3} + 1) \frac{d}{d x} (8 x^{3} + 1)

= sec (8 x^{3} + 1) tan (8 x^{3} + 1) \frac{d}{d x} (8 x^{3} + 1)

\frac{d}{d x} (8 x^{3} + 1) = 24 x^{2}

= sec (8 x^{3} + 1) tan (8 x^{3} + 1) \cdot 24 x^{2}

f (x) = 18 x, at x = 9

n = 2 \sum \infty \frac{7}{4 ^{n}}

x \to \infty lim (e^{x} x)

\int \frac{3}{x + 4} d x

x \to 4 lim ((2 x - 3)^{2})

What is the derivative of sec(8x^3+1) ?
The derivative of sec(8x^3+1) is sec(8x^3+1)tan(8x^3+1)*24x^2
What is the first derivative of sec(8x^3+1) ?
The first derivative of sec(8x^3+1) is sec(8x^3+1)tan(8x^3+1)*24x^2