What is (\partial)/(\partial x)(ln(x^6-y^4)) ?

The answer to (\partial)/(\partial x)(ln(x^6-y^4)) is (6x^5)/(x^6-y^4)

Popular >

(\partial)/(\partial x)(ln(x^6-y^4))

\frac{\partial}{\partial x} (ln (x^{6} - y^{4}))

\frac{6 x ^{5}}{x ^{6} - y ^{4}}

Solution steps

\frac{\partial}{\partial x} (ln (x^{6} - y^{4}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x ^{6} - y ^{4}} \frac{\partial}{\partial x} (x^{6} - y^{4})

= \frac{1}{x ^{6} - y ^{4}} \frac{\partial}{\partial x} (x^{6} - y^{4})

\frac{\partial}{\partial x} (x^{6} - y^{4}) = 6 x^{5}

= \frac{1}{x ^{6} - y ^{4}} \cdot 6 x^{5}

Simplify

\frac{1}{x ^{6} - y ^{4}} \cdot 6 x^{5} : \frac{6 x ^{5}}{x ^{6} - y ^{4}}

= \frac{6 x ^{5}}{x ^{6} - y ^{4}}

f (x) = 2 (x - 3)^{2} + 1, (4, 3)

\frac{d}{d t} (cos (\frac{t ^{3}}{10}))

x \to 2 lim (\frac{9 x}{x - 2})

\int x^{2} \cdot 3^{2 x} d x

n = 1 \sum \infty \frac{1}{n ^{0.7}}

What is (\partial)/(\partial x)(ln(x^6-y^4)) ?
The answer to (\partial)/(\partial x)(ln(x^6-y^4)) is (6x^5)/(x^6-y^4)