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Popular >

y^'=x^2(1+y^2)

Solution

y^{^{'}} = x^{2} (1 + y^{2})

Solution

y = tan (\frac{x ^{3}}{3} + c_{1})

Solution steps

y^{'} (x) = x^{2} (1 + y^{2})

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + c_{1})

y = tan (\frac{x ^{3}}{3} + c_{1})

Popular Examples

derivative of 42(7P+5)^5 derivative of

42 (7 P + 5)^{5}

y^'=(x(y+1))/(y(x+2))

y^{^{'}} = \frac{x ( y + 1 )}{y ( x + 2 )}

y^{^{'}} - y = 2 e^{2 t}

integral of 15sin^5(x)

\int 15 sin^{5} (x) d x

derivative of-e^{-x}x+e^{-x}

\frac{d}{d x} (- e^{- x} x + e^{- x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2(1+y^2) ?
The solution for y^'=x^2(1+y^2) is y=tan((x^3)/3+c_{1})