What is the solution for y^'=(x(y+1))/(y(x+2)) ?

The solution for y^'=(x(y+1))/(y(x+2)) is y=-\W(-((x+2)^2)/(e^{-c_{1)+x+2}})-1

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y^'=(x(y+1))/(y(x+2))

y^{^{'}} = \frac{x ( y + 1 )}{y ( x + 2 )}

y = - W (- \frac{( x + 2 ) ^{2}}{e ^{- c_{1} + x + 2}}) - 1

Solution steps

y^{'} (x) = \frac{x ( y + 1 )}{y ( x + 2 )}

Solve separable ODE:

y = - W (- \frac{( x + 2 ) ^{2}}{e ^{- c_{1} + x + 2}}) - 1

y = - W (- \frac{( x + 2 ) ^{2}}{e ^{- c_{1} + x + 2}}) - 1

y^{^{'}} - y = 2 e^{2 t}

\int 15 sin^{5} (x) d x

\frac{d}{d x} (- e^{- x} x + e^{- x})

y^{^{'}} = y^{2} - 100

x \to - 2 lim (- 4 x + a)

What is the solution for y^'=(x(y+1))/(y(x+2)) ?
The solution for y^'=(x(y+1))/(y(x+2)) is y=-\W(-((x+2)^2)/(e^{-c_{1)+x+2}})-1