What is the integral from-infinity to 0 of xe^{-8x} ?

The integral from-infinity to 0 of xe^{-8x} is diverges

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integral from-infinity to 0 of xe^{-8x}

\int_{- \infty}^{0} x e^{- 8 x} d x

diverges

Solution steps

\int_{- \infty}^{0} x e^{- 8 x} d x

Compute the indefinite integral:

\int x e^{- 8 x} d x = \frac{1}{64} (- 8 e^{- 8 x} x - e^{- 8 x}) + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{- 8 x} d x =

diverges

= diverges

(1 + 2 x)^{2}

y = \frac{7 x}{e ^{x}}

arctan (x - 1 + x^{2})

\int sin^{2} (4 x) \cdot cos^{2} (4 x) d x

f (x) = x^{5} - 5 x^{3} + x - 1

What is the integral from-infinity to 0 of xe^{-8x} ?
The integral from-infinity to 0 of xe^{-8x} is diverges