What is the integral from-infinity to 0 of xe^{-8x} ?

The integral from-infinity to 0 of xe^{-8x} is diverges

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integral from-infinity to 0 of xe^{-8x}

\int_{- \infty}^{0} x e^{- 8 x} d x

diverges

Solution steps

\int_{- \infty}^{0} x e^{- 8 x} d x

Compute the indefinite integral:

\int x e^{- 8 x} d x = \frac{1}{64} (- 8 e^{- 8 x} x - e^{- 8 x}) + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{- 8 x} d x =

diverges

= diverges

arctan (x - 1 + x^{2})

f (x) = x^{5} - 5 x^{3} + x - 1

(e^{2})^{^{'}}

\frac{d}{d θ} (2 a sin (θ))

(1 + x) d y = y d x

What is the integral from-infinity to 0 of xe^{-8x} ?
The integral from-infinity to 0 of xe^{-8x} is diverges