What is the integral of (x^3)/(x^2) ?

The integral of (x^3)/(x^2) is (x^2)/2+C

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integral of (x^3)/(x^2)

\int \frac{x ^{3}}{x ^{2}} d x

\frac{x ^{2}}{2} + C

Solution steps

\int \frac{x ^{3}}{x ^{2}} d x

Simplify

\frac{x ^{3}}{x ^{2}} : x

= \int x d x

Apply the Power Rule

= \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{2}}{2} + C

t e^{- t} cos (t)

\int 0. 8^{x} d x

\int (3 x^{2} - 2 x + 1) (x^{3} - x^{2} + x)^{9} d x

\int_{0}^{5} x + 1 d x

\frac{d y}{d t} = - \frac{t}{y}