What is laplacetransform 3tcos(2t) ?

The answer to laplacetransform 3tcos(2t) is -(3(-s^2+4))/((s^2+4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 3tcos(2t)

laplace transform

3 t cos (2 t)

- \frac{3 ( - s ^{2} + 4 )}{( s ^{2} + 4 ) ^{2}}

Solution steps

L {3 t cos (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {t cos (2 t)}

L {t cos (2 t)} : - \frac{- s ^{2} + 4}{( s ^{2} + 4 ) ^{2}}

= 3 (- \frac{- s ^{2} + 4}{( s ^{2} + 4 ) ^{2}})

Refine

3 (- \frac{- s ^{2} + 4}{( s ^{2} + 4 ) ^{2}}) : - \frac{3 ( - s ^{2} + 4 )}{( s ^{2} + 4 ) ^{2}}

= - \frac{3 ( - s ^{2} + 4 )}{( s ^{2} + 4 ) ^{2}}

\int e^{- 0.5 x} d x

\int (x^{2} + 4)^{7} d x

f (x) = x^{2} arctan (3 x)

\int y^{2} e^{x y} d x

f (x) = \frac{4 x}{x - 5}, at x = 7

What is laplacetransform 3tcos(2t) ?
The answer to laplacetransform 3tcos(2t) is -(3(-s^2+4))/((s^2+4)^2)