What is the tangent of f(x)=(4x)/(x-5),\at x=7 ?

The tangent of f(x)=(4x)/(x-5),\at x=7 is y=-5x+49

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tangent of f(x)=(4x)/(x-5),\at x=7

tangent of

f (x) = \frac{4 x}{x - 5}, at x = 7

y = - 5 x + 49

Solution steps

Find the tangent point:

(7, 14)

Find the slope of

f (x) = \frac{4 x}{x - 5} : \frac{df ( x )}{d x} = - \frac{20}{( x - 5 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x}{x - 5}

x = 7 : m = - 5

Find the line with slope m=

- 5

and passing through

(7, 14) : y = - 5 x + 49

y = - 5 x + 49

\frac{\partial}{\partial x} (ln (\frac{x}{y - z}))

\frac{\partial}{\partial y} (y^{2} cos (y))

x \to 3 lim (\frac{x ^{2} + 1}{x - 2})

f (x) = (x^{3} + 5) e^{x}

\int_{- \infty}^{0} e^{- 2 x} d x

What is the tangent of f(x)=(4x)/(x-5),\at x=7 ?
The tangent of f(x)=(4x)/(x-5),\at x=7 is y=-5x+49