What is the solution for y^{''}+10y^'+21y=0 ?

The solution for y^{''}+10y^'+21y=0 is y=c_{1}e^{-3t}+c_{2}e^{-7t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+10y^'+21y=0

y^{^{''}} + 10 y^{^{'}} + 21 y = 0

y = c_{1} e^{- 3 t} + c_{2} e^{- 7 t}

Solution steps

y^{''} (t) + 10 y^{'} (t) + 21 y = 0

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} e^{- 7 t}

y = c_{1} e^{- 3 t} + c_{2} e^{- 7 t}

(9 x + 2)^{\frac{2}{3}}

\int (4 x + 2) (x - 1) d x

y^{^{'}} + y = 5 x y^{3}

\int \frac{1}{1 - t} d t

x \to 1 lim (e^{x^{5} - x})

What is the solution for y^{''}+10y^'+21y=0 ?
The solution for y^{''}+10y^'+21y=0 is y=c_{1}e^{-3t}+c_{2}e^{-7t}