What is the derivative of x^3-2x^2+1 ?

The derivative of x^3-2x^2+1 is 3x^2-4x

What is the first derivative of x^3-2x^2+1 ?

The first derivative of x^3-2x^2+1 is 3x^2-4x

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\frac{d}{d x} (x^{3} - 2 x^{2} + 1)

3 x^{2} - 4 x

Solution steps

\frac{d}{d x} (x^{3} - 2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 3 x^{2} - 4 x + 0

Simplify

= 3 x^{2} - 4 x

e^{(- 2 s)}

\frac{d y}{d x} = 4 x e^{6 y}

\int x ln (5 x) d x

\frac{d}{d x} ((x^{2} - \frac{5}{4}) e^{x})

\frac{\partial}{\partial x} (sin (x^{2} \cdot y^{2}))

What is the derivative of x^3-2x^2+1 ?
The derivative of x^3-2x^2+1 is 3x^2-4x
What is the first derivative of x^3-2x^2+1 ?
The first derivative of x^3-2x^2+1 is 3x^2-4x