What is the derivative of f(x)=6x^{1.5}-4x^{0.5} ?

The derivative of f(x)=6x^{1.5}-4x^{0.5} is (-2+9x)/(x^{1/2)}

What is the first derivative of f(x)=6x^{1.5}-4x^{0.5} ?

The first derivative of f(x)=6x^{1.5}-4x^{0.5} is (-2+9x)/(x^{1/2)}

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derivative of

f (x) = 6 x^{1.5} - 4 x^{0.5}

\frac{- 2 + 9 x}{x ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} (6 x^{1.5} - 4 x^{0.5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{1.5}) - \frac{d}{d x} (4 x^{0.5})

\frac{d}{d x} (6 x^{1.5}) = 9 x^{0.5}

\frac{d}{d x} (4 x^{0.5}) = \frac{2}{x ^{0.5}}

= 9 x^{0.5} - \frac{2}{x ^{0.5}}

Simplify

9 x^{\frac{1}{2}} - \frac{2}{x ^{\frac{1}{2}}} : \frac{- 2 + 9 x}{x ^{\frac{1}{2}}}

= \frac{- 2 + 9 x}{x ^{\frac{1}{2}}}

\int e^{9} d y

\frac{d y}{d x} - 4 tan (2 x) = sin (2 x)

x \to - 3 lim (- 3)

\int_{0}^{1} \frac{1}{( 2 x + 1 ) ^{3}} d x

V (r) = (\frac{4}{3}) π r^{3}

What is the derivative of f(x)=6x^{1.5}-4x^{0.5} ?
The derivative of f(x)=6x^{1.5}-4x^{0.5} is (-2+9x)/(x^{1/2)}
What is the first derivative of f(x)=6x^{1.5}-4x^{0.5} ?
The first derivative of f(x)=6x^{1.5}-4x^{0.5} is (-2+9x)/(x^{1/2)}