What is the derivative of y=\sqrt[9]{x^8}-x^pi ?

The derivative of y=\sqrt[9]{x^8}-x^pi is (8x^7)/(9(x^8)^{8/9)}-pix^{pi-1}

What is the first derivative of y=\sqrt[9]{x^8}-x^pi ?

The first derivative of y=\sqrt[9]{x^8}-x^pi is (8x^7)/(9(x^8)^{8/9)}-pix^{pi-1}

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derivative of

\frac{8 x ^{7}}{9 ( x ^{8} ) ^{\frac{8}{9}}} - π x^{π - 1}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x^{π}) = π x^{π - 1}

= \frac{8 x ^{7}}{9 ( x ^{8} ) ^{\frac{8}{9}}} - π x^{π - 1}

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What is the derivative of y=\sqrt[9]{x^8}-x^pi ?
The derivative of y=\sqrt[9]{x^8}-x^pi is (8x^7)/(9(x^8)^{8/9)}-pix^{pi-1}
What is the first derivative of y=\sqrt[9]{x^8}-x^pi ?
The first derivative of y=\sqrt[9]{x^8}-x^pi is (8x^7)/(9(x^8)^{8/9)}-pix^{pi-1}