What is (\partial)/(\partial y)(1+3x+2y^2) ?

The answer to (\partial)/(\partial y)(1+3x+2y^2) is 4y

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(\partial)/(\partial y)(1+3x+2y^2)

\frac{\partial}{\partial y} (1 + 3 x + 2 y^{2})

4 y

Solution steps

\frac{\partial}{\partial y} (1 + 3 x + 2 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) + \frac{\partial}{\partial y} (3 x) + \frac{\partial}{\partial y} (2 y^{2})

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (2 y^{2}) = 4 y

= 0 + 0 + 4 y

Simplify

= 4 y

\frac{d}{d x} (\frac{x + 1}{x ^{2} + 1})

y = - 8

\frac{\partial}{\partial y} (\frac{m}{y} - 625 \frac{y}{x})

f (x) = x^{3} (x^{2} + 4)^{- 2}

4 \cdot e^{2 x}

What is (\partial)/(\partial y)(1+3x+2y^2) ?
The answer to (\partial)/(\partial y)(1+3x+2y^2) is 4y