What is the solution for (dy)/(dx)+(3/x)y=-2x-7 ?

The solution for (dy)/(dx)+(3/x)y=-2x-7 is y=-(2x^2)/5-(7x)/4+(c_{1})/(x^3)

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(dy)/(dx)+(3/x)y=-2x-7

\frac{d y}{d x} + (\frac{3}{x}) y = - 2 x - 7

y = - \frac{2 x ^{2}}{5} - \frac{7 x}{4} + \frac{c _{1}}{x ^{3}}

Solution steps

\frac{d y}{d x} + (\frac{3}{x}) y = - 2 x - 7

Solve linear ODE:

y = - \frac{2 x ^{2}}{5} - \frac{7 x}{4} + \frac{c _{1}}{x ^{3}}

y = - \frac{2 x ^{2}}{5} - \frac{7 x}{4} + \frac{c _{1}}{x ^{3}}

3 sin (x), 4 cos (x), [0, 0.8 π]

\frac{d}{d x} (- 4 sec^{2} (x) + 6 sec^{4} (x))

x \to 3 lim (- 3 x - 7)

e^{u}

\int cos^{10} (x) d x

What is the solution for (dy)/(dx)+(3/x)y=-2x-7 ?
The solution for (dy)/(dx)+(3/x)y=-2x-7 is y=-(2x^2)/5-(7x)/4+(c_{1})/(x^3)