What is the derivative of-14e^{-x^2}x ?

The derivative of-14e^{-x^2}x is -14(-2e^{-x^2}x^2+e^{-x^2})

What is the first derivative of-14e^{-x^2}x ?

The first derivative of-14e^{-x^2}x is -14(-2e^{-x^2}x^2+e^{-x^2})

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derivative of

- 14 e^{- x^{2}} x

- 14 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}})

Solution steps

\frac{d}{d x} (- 14 e^{- x^{2}} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 14 \frac{d}{d x} (e^{- x^{2}} x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- x^{2}}, g = x

= - 14 (\frac{d}{d x} (e^{- x^{2}}) x + \frac{d x}{d x} e^{- x^{2}})

\frac{d}{d x} (e^{- x^{2}}) = - 2 e^{- x^{2}} x

\frac{d x}{d x} = 1

= - 14 ((- 2 e^{- x^{2}} x) x + 1 \cdot e^{- x^{2}})

Simplify

- 14 ((- 2 e^{- x^{2}} x) x + 1 \cdot e^{- x^{2}}) : - 14 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}})

= - 14 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}})

3 (y^{4} + 1) d x + (4 x y^{3}) d y = 0

x \to - 2 lim (x^{2} + 2 x - 1)

\int \frac{1}{( y - 1 )} d y

\int x^{3} (x^{4} - 9)^{4} d x

x \to 4 lim (20 - x^{2})

What is the derivative of-14e^{-x^2}x ?
The derivative of-14e^{-x^2}x is -14(-2e^{-x^2}x^2+e^{-x^2})
What is the first derivative of-14e^{-x^2}x ?
The first derivative of-14e^{-x^2}x is -14(-2e^{-x^2}x^2+e^{-x^2})