What is the derivative of 6sin(x)-8e^x ?

The derivative of 6sin(x)-8e^x is 6cos(x)-8e^x

What is the first derivative of 6sin(x)-8e^x ?

The first derivative of 6sin(x)-8e^x is 6cos(x)-8e^x

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derivative of

6 sin (x) - 8 e^{x}

6 cos (x) - 8 e^{x}

Solution steps

\frac{d}{d x} (6 sin (x) - 8 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 sin (x)) - \frac{d}{d x} (8 e^{x})

\frac{d}{d x} (6 sin (x)) = 6 cos (x)

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

= 6 cos (x) - 8 e^{x}

\frac{d y}{d x} = cos (x) (1 + 3 y)

\frac{\partial}{\partial x} (x^{6} y^{6} + 4 x^{6} y)

\frac{\partial}{\partial x} (x \cdot e^{- x^{2} - y^{2}})

\int x 2 - x^{2} d x

\frac{x ^{2} d y}{d x} = y - x y, y [- 1] = - 4

What is the derivative of 6sin(x)-8e^x ?
The derivative of 6sin(x)-8e^x is 6cos(x)-8e^x
What is the first derivative of 6sin(x)-8e^x ?
The first derivative of 6sin(x)-8e^x is 6cos(x)-8e^x