What is (\partial)/(\partial x)((sin(x))/(y^2)) ?

The answer to (\partial)/(\partial x)((sin(x))/(y^2)) is (cos(x))/(y^2)

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(\partial)/(\partial x)((sin(x))/(y^2))

\frac{\partial}{\partial x} (\frac{sin ( x )}{y ^{2}})

\frac{cos ( x )}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{sin ( x )}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y ^{2}} \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= \frac{1}{y ^{2}} cos (x)

Simplify

\frac{1}{y ^{2}} cos (x) : \frac{cos ( x )}{y ^{2}}

= \frac{cos ( x )}{y ^{2}}

\frac{\partial}{\partial u ( v )} (\frac{e ^{v}}{u ( v ) + v ^{7}})

\int \frac{1}{x ^{2} - 169} d x

\int_{2}^{4} \frac{x}{6} (2 x - 3) d x

\int_{- 2}^{2} \frac{12}{x ^{2} - 4 x - 32} d x

\frac{d}{d x} (sin^{2} (x^{3}))

What is (\partial)/(\partial x)((sin(x))/(y^2)) ?
The answer to (\partial)/(\partial x)((sin(x))/(y^2)) is (cos(x))/(y^2)