What is the integral from 1 to 10 of 1/(4x^3) ?

The integral from 1 to 10 of 1/(4x^3) is 99/800

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integral from 1 to 10 of 1/(4x^3)

\int_{1}^{10} \frac{1}{4 x ^{3}} d x

\frac{99}{800}

Decimal Notation

0.12375

Solution steps

\int_{1}^{10} \frac{1}{4 x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{1}^{10} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{10}

= \frac{1}{4} [- \frac{1}{2 x ^{2}}]_{1}^{10}

Compute the boundaries:

\frac{99}{200}

= \frac{1}{4} \cdot \frac{99}{200}

Simplify

= \frac{99}{800}

\frac{d}{d x} (10 x + 1)

\frac{d}{d x} (7 x^{2} e^{- x})

x \to - 0 lim (e^{- \frac{1}{x}})

\int_{2}^{- 1} 3 x (x - 4) d x

\int_{0}^{1} \frac{1}{x + 1} d x

What is the integral from 1 to 10 of 1/(4x^3) ?
The integral from 1 to 10 of 1/(4x^3) is 99/800