What is the solution for (dy}{dx}=-\frac{e^x)/8 ?

The solution for (dy}{dx}=-\frac{e^x)/8 is y=-1/8 e^x+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=-\frac{e^x)/8

\frac{d y}{d x} = - \frac{e ^{x}}{8}

y = - \frac{1}{8} e^{x} + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{e ^{x}}{8}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = - \frac{e ^{x}}{8}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - \frac{e ^{x}}{8} d x

\int - \frac{e ^{x}}{8} d x = - \frac{1}{8} e^{x} + c_{1}

y = - \frac{1}{8} e^{x} + c_{1}

\int sec^{2} (3 x) tan^{3} (3 x) d x

x \cdot 6^{x}

\frac{\partial}{\partial y} (\frac{x}{7 + y})

\int sin^{3} (x) \cdot cos^{4} (x) d x

\frac{d}{d x} (arctan (x) d x)

What is the solution for (dy}{dx}=-\frac{e^x)/8 ?
The solution for (dy}{dx}=-\frac{e^x)/8 is y=-1/8 e^x+c_{1}